Question

Two particles of masses $4$ $kg$ and $6$ $kg$ are at rest separated by $20$ $m$. If they move towards each other under mutual force of attraction, the position of the point where they meet is

• A. $12$ $m$ from $4$ $kg$ body
• B. $12$ $m$ from $6$ $kg$ body
• C. $8$ $m$ from $4$ $kg$ body
• D. $10$ $m$ from $4$ $kg$ body

Answer 1

The correct option is A $12$ $m$ from $4$ $kg$ body

$F\propto m$

$F\propto \frac{1}{r}$

more force need for more mass block and less movement for more mass block.

$\Rightarrow \frac{m_1}{r_1}=\frac{m_2}{r_2}$

$\Rightarrow \frac{r_2}{r_1}=\frac{m_1}{m_2}=\frac{2}{3}$

$\Rightarrow \frac{r_1}{r_2}=\frac{3}{2}$

$12$ $m$ from $4$ $kg$ body.