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Question

Two particles of same mass 2 kg are rigidly attached to the ends of a massless rod of length 10 m. The rod is clamped at the centre such that the system rotates about the perpendicular bisector of the rod at an angular speed 10 rad/s. Calculate the magnitude of angular momentum of the system about the axis of rotation [in kg m2/s]


A
100
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B
1000
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C
500
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D
10
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Solution

The correct option is B 1000
As we know,
Lsystem=Iaxisω
where, I= MOI of the system about the axis of rotation
I=m1r21+m2r22
I=2×(102)2+2×(102)2
I=100 kg-m2
& ω=10 rad/s

From , Lsystem=Iaxisω
Lsystem=100×10
Lsystem=1000 kg m2/s

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