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Standard XII

Physics

Horizontal and Vertical Components of Projectile Motion

Two particles...

Question

Two particles P and Q are in motion. Their displacement time graphs are respectively inclined at $30^{\circ}$ and $60^{\circ}$ to time axis. Their ratio of velocities $\frac{V_{P}}{V_{Q}}$ is

1 : \sqrt{3}

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\sqrt{3} : \sqrt{2}

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1:2

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1:3

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Solution

The correct option is D 1:3
Velocity = Slope of the line formed in displacement v/s time graph = Tanθ

Vp : Vq = Tan30 : Tan60 = (1/√3) : √3= 1 : 3

Ratio of velocities of P:Qis 1 : 3

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The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

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Two particles P and Q are in motion. Their displacement time graphs are respectively inclined at 30∘ and 60∘ to time axis. Their ratio of velocities VPVQ is

The correct option is D 1:3Velocity = Slope of the line formed in displacement v/s time graph = Tanθ Vp : Vq = Tan30 : Tan60 = (1/√3) : √3= 1 : 3 Ratio of velocities of P:Qis 1 : 3

Two particles P and Q are in motion. Their displacement time graphs are respectively inclined at $30^{\circ}$ and $60^{\circ}$ to time axis. Their ratio of velocities $\frac{V_{P}}{V_{Q}}$ is

The correct option is D 1:3
Velocity = Slope of the line formed in displacement v/s time graph = Tanθ

Vp : Vq = Tan30 : Tan60 = (1/√3) : √3= 1 : 3

Ratio of velocities of P:Qis 1 : 3