Question

Two particles P and Q describe SHM of same amplitude a and frequency v along the same straight line. The maximum distance between the two particles is $a\sqrt{2}$. The initial phase difference between the particle is

• A. $\pi /3$
• B. $\pi /2$
• C. $\pi /6$
• D. zero

Answer 1

The correct option is B $\pi /2$

Let initial phase difference be $\theta$

So, distance between two particales is $d=asin(\omega t+\theta )-asin\left(\omega t\right)=2asin\left(\theta /2\right)cos(\omega t+\theta /2)$

As maximum value of $d$ is $a\sqrt{2}$, so $2asin\left(\theta /2\right)=a\sqrt{2}\Rightarrow \theta =\pi /2$