Question

Two particles P and Q start from origin and execute S.H.M along x-axis with same amplitude but with periods 3 seconds and 6 seconds respectively. The ratio of the velocities of P and Q when they are at mean position is

• A. 1 : 2
• B. 2 : 1
• C. 2 : 3
• D. 3 : 2

Answer 1

Answer: (B)

2 : 1

Velocity at mean position $=V_{max}$
$V_{max}=A\omega$
$\omega =\frac{2\pi }{T}$

$V_1=\frac{A2\pi }{T_1}$ {$\therefore A_1=A_2=A$ }

$V_2=\frac{A\times 2\pi }{T_2}$

$\frac{V_1}{V_2}=\frac{T_2}{T_1}$

$\frac{V_1}{V_2}=\frac{6}{3}$

$\frac{V_1}{V_2}=\frac{2}{1}$