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Standard XII

Physics

Relative Velocity in 2D

Two particles...

Question

Two particles P and Q start their journey simultaneously from point A. P moves along a smooth horizontal wire AB. Q moves along a curved smooth track. Q has sufficient velocity at A to reach B always remaining in contact with the curved track. At A, the horizontal component of velocity of Q is same as the velocity of P along the wire. The plane of motion is vertical. If $t_{1}, t_{2},$ are times taken by P & Q respectively to reach B then (Assume velocity of P is constant)

t_{1} = t_{2}

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t_{1} > t_{2}

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t_{1} < t_{2}

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none of these

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Solution

The correct option is A $t_{1} = t_{2}$
As there is no acceleration in the horizontal direction for Q, there is no change of velocity in horizontal direction. As the displacement for both the particle is same so
$∴ t_{1} = t_{2}$

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From above graph choose correct option for $t_{1}$ to $t_{2}$ where $t_{1}$ is the time at which velocity of particle = 0 $t_{2}$ is the time at which velocity of particle is negative.

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The correct option is A t1=t2As there is no acceleration in the horizontal direction for Q, there is no change of velocity in horizontal direction. As the displacement for both the particle is same so∴t1=t2

The correct option is A $t_{1} = t_{2}$
As there is no acceleration in the horizontal direction for Q, there is no change of velocity in horizontal direction. As the displacement for both the particle is same so
$∴ t_{1} = t_{2}$