Two particles separated at a horizonal distance x as shown in fig. they projected at the same line as shown in fig. with different initial speeds. The time after which the horizontal distance between them become zero :
A
xu
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B
u2x
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C
2ux
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D
noneofthese
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Solution
The correct option is Axu let the horizontal component of both particles be u√3cos30o=u2 and ucos60o=u2 respectively
therefore let l be the distance covered by particle and l-x for particle 2 therefore
l=u2t and x−l=u2t
solving above equations we get l=x2 therefore t=xu