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Question

Two particles start simultaneously from points A and B as shown in the figure. Then what is the minimum distance between them?

A
5 m
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B
10 m
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C
15 m
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D
20 m
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Solution

The correct option is B 10 m
Let VAB be the relative velocity of A w.r.t B.
VA=10cos45^i+10sin 45^j
VA=5^i+5^j
VB=5^j
Hence, VAB=VAVB=5^i+25^j

Let α be the angle that VAB makes with the line AB.
tanα=255=2
Let dmin be the minimum distance between the particles.
From the figure,
dmin=55sinα=55×25=10 m

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