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Standard XII

Physics

Wave Equation

Two particles...

Question

Two particles undergo SHM along same line with same time period (T) and same amplitude (A) At particular instant one particle is x = - A and the other is at x = 0 If they move in same direction then they will meet each other at

x = \frac{A}{2}

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x = \frac{A}{\sqrt{2}}

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x = \frac{A}{4}

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x = \frac{4}{8}

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Solution

The correct option is A $x = \frac{A}{\sqrt{2}}$
Representing the SHM in ordinance motion.
As we see the projection of the balls meet at distance $A sin 45^{o} = \frac{A}{\sqrt{2}}$ .

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Two particles undergo SHM along same line with same time period (T) and same amplitude (A) At particular instant one particle is x = - A and the other is at x = 0 If they move in same direction then they will meet each other at

The correct option is A x=A√2Representing the SHM in ordinance motion.As we see the projection of the balls meet at distance Asin45o=A√2.

The correct option is A $x = \frac{A}{\sqrt{2}}$
Representing the SHM in ordinance motion.
As we see the projection of the balls meet at distance $A sin 45^{o} = \frac{A}{\sqrt{2}}$ .