Question

Two pea plants, one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that has round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have a new combination of characters. Choose the new combination from the following

(i) Round, yellow

(ii) Round, green

(iii) Wrinkled, yellow

(iv) Wrinkled, green

• A. (i) and (ii)
• B. (i) and (iv)
• C. (ii) and (iii)
• D. (i) and (iii)

Answer 1

The correct option is B

(i) and (iv)

The correct option is B.

Explanation of the correct option:

1. The phenotypic ratio 9:3:3:1 is obtained.

Parents: RRyy (Round green) X rrYY (Wrinkled Yellow)

Gametes: Ry rY

F1: RrYy

Selfing of F1: RrYy (Round yellow) X RrYy (Round yellow)

Gametes: RY, Ry, rY and ry X RY, Ry, rY and ry

F2: RRYY, RRYy, RrYY, RrYy (Round yellow)

RRYy, RRyy, RrYy, Rryy (Round yellow)

RrYY, RrYy, RrYy, Rryy, (Round yellow)

rrYY, rrYy, rrYy (Wrinkled yellow)

rryy (Wrinkled green)

Final answer: Two pea plants, one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that has round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have a new combination of characters, the combination will be round, yellow and wrinkled green.