Question

Two pendula have time periods T and $\frac{5T}{4}$. They start SHM at the same time from the mean position. The phase difference between them after the pendulum with larger period completes one oscillation is

• A. $\frac{\pi }{3}$
• B. $\frac{\pi }{6}$
• C. $\frac{\pi }{2}$
• D. $\pi$

Answer 1

The correct option is C $\frac{\pi }{2}$

Since $\frac{5T}{4}=T+\frac{T}{4}$, the phase difference is $\frac{\pi }{2}$.