Two pendula start swinging simultaneously. By the time first pendulum makes 20 oscillations, $2^{n} d$ pendulum makes 15 oscillations. The ratio of their lengths is

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Solution

The correct option is A

$\frac{f_{1}}{f_{2}} = \sqrt{\frac{l_{2}}{l_{1}}} = \frac{20}{15} \Rightarrow \frac{l_{1}}{l_{2}} = \frac{225}{400} = \frac{9}{16}$

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Two pendula start swinging simultaneously. By the time first pendulum makes 20 oscillations, 2nd pendulum makes 15 oscillations. The ratio of their lengths is

The correct option is A f1f2=√l2l1=2015⇒l1l2=225400=916

Two pendula start swinging simultaneously. By the time first pendulum makes 20 oscillations, $2^{n} d$ pendulum makes 15 oscillations. The ratio of their lengths is

The correct option is A

$\frac{f_{1}}{f_{2}} = \sqrt{\frac{l_{2}}{l_{1}}} = \frac{20}{15} \Rightarrow \frac{l_{1}}{l_{2}} = \frac{225}{400} = \frac{9}{16}$