Two pendula start swinging simultaneously. By the time the first pendulum makes 20 oscillations, $2^{n d}$ pendulum makes 15 oscillations. The ratio of their lengths is:

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Solution

The correct option is A

$\frac{f_{1}}{f_{2}} = \sqrt{\frac{l_{2}}{l_{1}}}$
$= \frac{20}{15} \Rightarrow \frac{l_{1}}{l_{2}}$
$= \frac{225}{400} = \frac{9}{16}$

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Two pendula start swinging simultaneously. By the time the first pendulum makes 20 oscillations, 2nd pendulum makes 15 oscillations. The ratio of their lengths is:

The correct option is A f1f2=√l2l1 =2015⇒l1l2 =225400=916

Two pendula start swinging simultaneously. By the time the first pendulum makes 20 oscillations, $2^{n d}$ pendulum makes 15 oscillations. The ratio of their lengths is:

The correct option is A

$\frac{f_{1}}{f_{2}} = \sqrt{\frac{l_{2}}{l_{1}}}$
$= \frac{20}{15} \Rightarrow \frac{l_{1}}{l_{2}}$
$= \frac{225}{400} = \frac{9}{16}$