Two pendulums of lengths 1.44m and 1m start to swing together. The number of vibrations after which they will again start swinging together is
A
4
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B
3
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C
6
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D
2
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E
5
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Solution
The correct option is E5 If t is the time taken by pendulums to come in same phase again first time after t=0. Then, (n+1)2π√l1g=n2π√l2g (n−1)×√1.44=n (n−1)=1.2n (n+1)=1.2n n=10.2=5