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Two periodic ...

Question

Two periodic waves of amplitudes $A_{1}$ and $A_{2}$ pass through a region. If $A_{1} > A_{2}$ , the difference in the maximum and minimum resultant amplitude possible is

A

2 A_{1}

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B

2 A_{2}

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C

A_{1} - A_{2}

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D

A_{1} + A_{2}

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Solution

The correct option is B $2 A_{2}$
Given amplitude of the two waves are $A_{1}$ and $A_{2}$
$A_{m a x} - A_{m i n} = (A_{1} + A_{2}) - (A_{1} - A_{2})$
$= 2 A_{2}$
Final answer: (b)

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