Question

Two person A and B toss a die one after another. The person who throws a 6 wins. If A starts the game, then the probability of his winning is

• A. $\frac{4}{11}$
• B. $\frac{3}{11}$
• C. $\frac{5}{11}$
• D. $\frac{6}{11}$

Answer 1

The correct option is D $\frac{6}{11}$

$P\left(W\right)=\frac{1}{6},P\left(L\right)=\frac{5}{6}P\left(A\right)=\frac{1}{6}+{\left(\frac{5}{6}\right)}^2.\frac{1}{6}+{\left(\frac{5}{6}\right)}^4.\frac{1}{6}+.....=\frac{6}{11}$