Two persons A and B are $350$ m apart .If A can run at the speed of $7$ m/sec and B can run at the speed of $3$ m/sec; Find in how much time will they meet each other , if they run in the opposite directions ?

35

sec

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22

sec

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75

sec

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49

sec

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Solution

The correct option is A $35$ sec
$t i m e = \frac{d i s t a n c e}{s p e e d}$
When two objects are moving in opposite directions at x m/s and y m/s, then their $r e l a t i v e s p e e d = (x + y) m / s$
Therefore, $r e l a t i v e s p e e d = 7 + 3 = 10 m / s$
$d i s t a n c e = 350 m$
$\Rightarrow t i m e = \frac{350}{10} = 35 s e c$

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Two persons A and B are 350 m apart .If A can run at the speed of 7 m/sec and B can run at the speed of 3 m/sec; Find in how much time will they meet each other , if they run in the opposite directions ?

The correct option is A 35 sectime=distancespeedWhen two objects are moving in opposite directions at x m/s and y m/s, then their relative speed=(x+y) m/sTherefore, relative speed=7+3=10 m/sdistance=350 m⇒time=35010=35 sec

Two persons A and B are $350$ m apart .If A can run at the speed of $7$ m/sec and B can run at the speed of $3$ m/sec; Find in how much time will they meet each other , if they run in the opposite directions ?