Question

Two persons having mass $50$ kg each, are standing such that their centre of gravities are $1m$ apart. Calculate the force of gravitation between them.

(Take $G=6.67\times {10}^{-11}N{m}^{2}k{g}^{-2}$, mass of earth $M=6\times {10}^{24}kg$, Radius of earth $R=6.4\times {10}^{6}m$)

• A. $2.67\times {10}^{-7}N$
• B. $1.67\times {10}^{-7}N$
• C. $1.32\times {10}^{-7}N$
• D. $1.67\times {10}^{-9}N$

Answer 1

Answer: (B)

$1.67\times {10}^{-7}N$

When both masses are equal then,

As we know that Gravitational force is given by:

$F=\frac{{GM}^2}{R^2}=\frac{6.67\times {10}^{-11}\times 50\times 50}{1\times 1}=1.67\times {10}^{-7}N$