Two persons P and Q start at the same time from city A for city B, 60 km away. P travels 4 kmph slower than Q. Q reaches city B and at once turns back meeting P, 12 km from city B. What is speed of P?

8 kmph

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12 kmph

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16 kmph

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20 kmph

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Solution

The correct option is A 8 kmph
$A B = 60 k m$ , $B C = 12 k m$ , $A C = 48 k m$
Let the speed of P be x kmph so that speed of Q is $(x + 4) k m p h$ . Time for P to cover a distance AC and time for Q to cover $(A B + B C)$ are equal.
$∴ \frac{72}{x + 4} = \frac{48}{x} ⟹ x = 8 k m p h$

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Two persons P and Q start at the same time from city A for city B, 60 km away. P travels 4 kmph slower than Q. Q reaches city B and at once turns back meeting P, 12 km from city B. What is speed of P?

The correct option is A 8 kmphAB=60km, BC=12km, AC=48kmLet the speed of P be x kmph so that speed of Q is (x+4)kmph. Time for P to cover a distance AC and time for Q to cover (AB+BC) are equal.∴72x+4=48x⟹x=8kmph

The correct option is A 8 kmph
$A B = 60 k m$ , $B C = 12 k m$ , $A C = 48 k m$
Let the speed of P be x kmph so that speed of Q is $(x + 4) k m p h$ . Time for P to cover a distance AC and time for Q to cover $(A B + B C)$ are equal.
$∴ \frac{72}{x + 4} = \frac{48}{x} ⟹ x = 8 k m p h$