Question

Two persons pull a rope towards themselves. Each person exerts a force of 100 N on the rope. Find the Young modulus of the material of the rope if it extends in length by 1 cm. Original length of the rope = 2m and the area of cross section = $2c{m}^2.$

Answer 1

F = 100 N,

L = 2 m,

$\Delta L$= 0.01 m

A = $2\times {10}^{-4}$

Y = $\frac{F}{A}\times \frac{L}{\Delta L}$

= $\frac{100}{2\times {10}^{-4}}\times \frac{1}{0.01}$

= $1\times {10}^{8}N/m^2$