Question

Two persons pull a rope towards themselves. Each person exerts a force of $100N$ on the rope. The Young's modulus $\left(N/m^2\right)$ of the material of the rope if it extends in length by $1cm,$ is ${10}^x.$ Find $x.$ Original length of the rope $=2m$ and the area of cross-section $=2c{m}^2.$

Answer 1

Step 1: Draw a labelled diagram.

Step2: Find the vslue of $x$
As we know
$\Delta L=\frac{FL}{AY}$

$Y=\frac{FL}{A\Delta L}=\frac{100N}{2\times {10}^{-4}\times 1\times {10}^{-2}}$

$={10}^{8}N/m^2$

Final Answer: (8)