Two photons have wave numbers in the ratio 2 : 3. Their energies will be in the ratio:

3 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 2 : 3
We know,
$E = h c ¯ ν$
$\Rightarrow E_{1} : E_{2} =_{1} :_{2} = 2 : 3$ [Since h and c are constant]

Suggest Corrections

Similar questions

Two waves of the same pitch have their amplitudes in the ratio 2:3.

The ratio of their loudness will be:

1 : 3

\frac{m_{1}}{m_{2}} = 3

\frac{E_{1}}{E_{2}} = \frac{1}{3}

Join BYJU'S Learning Program