Two pillars of height 8 m and 14 m are 8m apart, find the distance between their top.
10 m
The figure illustrates the situation explained in the question.
From the figure, we can say that,
AE = BC = 8 m ...(1)
BD = BC + CD
⇒14=8+CD⇒CD=6 m
Also, AB = EC = 8 m.
Now applying Pythagoras theorem on △CDE, we get,
ED2=EC2+DC2⇒ED2=82+62⇒ED2=64+36 =100⇒ED=10 m
Hence, the distance between their top = ED = 10 m.