Two pipes A and B can fill a tank in 20 hrs and 30 hrs respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

12

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\frac{1}{12}

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13

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\frac{1}{13}

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Solution

The correct option is A $12$
A and B
$↓$ $↓$
$20 h r$ $30 h r s$
$= \frac{1}{A} + \frac{1}{B} = \frac{1}{20} + \frac{1}{30} = \frac{5}{60} = \frac{1}{12}$
$= 12 h r s$

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Q. Tick (✓) the correct answer:
Two pipes can fill a tank in 10 hours and 12 hours respectively, while a third pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be full?
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(b) 7 hrs 30 min
(c) 7 hrs 45 min
(d) 8 hrs

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Two pipes A and B can fill a tank in 20 hrs and 30 hrs respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

The correct option is A 12A and B↓ ↓20hr 30hrs=1A+1B=120+130=560=112=12hrs

The correct option is A $12$
A and B
$↓$ $↓$
$20 h r$ $30 h r s$
$= \frac{1}{A} + \frac{1}{B} = \frac{1}{20} + \frac{1}{30} = \frac{5}{60} = \frac{1}{12}$
$= 12 h r s$