Two pipes A and B can fill a tank in 24 minutes and 32 minutes respectively. If both the pipes are opened simultaneously, after how much time should B be closed so that the tank is full in 18 minutes
A
2 min
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B
4 min
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C
6 min
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D
8 min
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Solution
The correct option is D 8 min Let the total capacity of the tank be 96 units (LCM of 24 & 32). A fills = 9624 = 4 units / minute. B fills = 9632 = 3 units / minute. Let the time for which B is opened is x minutes. According to the question, 4 × 18 + 3 × x = 96 3x = 96 - 72 = ⇒ 3x = 24 x = 8 minutes. The pipe B should be closed after 8 minutes.