Two pipes A and B can fill a tank in $36$ hours and $45$ hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

50

hours

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6

hours

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20

hours

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10

hours

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Solution

The correct option is D $20$ hours
Part filled by $A$ in $1$ hour $= \frac{1}{36}$
Part filled by $B$ in $1$ hour $= \frac{1}{45}$ ;
Part filled by $(A + B)$ in $1$ hour $= \frac{1}{36} + \frac{1}{45} = \frac{9}{180} = \frac{1}{20}$
Hence, both the pipes together will fill the tank in $20$ hours.

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Two pipes A and B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

The correct option is D 20 hoursPart filled by A in 1 hour =136Part filled by B in 1 hour =145;Part filled by (A+B) in 1 hour =136+145=9180=120Hence, both the pipes together will fill the tank in 20 hours.

Two pipes A and B can fill a tank in $36$ hours and $45$ hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?

The correct option is D $20$ hours
Part filled by $A$ in $1$ hour $= \frac{1}{36}$
Part filled by $B$ in $1$ hour $= \frac{1}{45}$ ;
Part filled by $(A + B)$ in $1$ hour $= \frac{1}{36} + \frac{1}{45} = \frac{9}{180} = \frac{1}{20}$
Hence, both the pipes together will fill the tank in $20$ hours.