Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
6 hrs
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
∴ 1x+1(x+6)=14x+6+xx(x+6)=14x2−2x−24=0 (x−6)(x+4)=0x=6 [neglecting the − ve value of x]