Two pipes running together can fill a tank in 1119 minutes. If one tap takes 5 mintues more than the other to fill the tank separately, find the time in which each pipe would fill the tank separately.
Let one of the pipe take x minutes to then the slower pipe will take (x+5) minutes.
Time taken by both pipe to fill the tank = minutes
Portion of tank filled by faster pipe in 1 minute =
Portion of tank filled by faster pipe in 1 minute =
Portion of tank filled by both pipe in one 1 minute = =
A/q,
⇒ 200x + 500 = 9x2 + 45x
⇒ 9x2 + 45x - 200x - 500 = 0
⇒ 9x2 - 155x - 500 = 0
⇒ 9x2 - 180x + 25x - 500 = 0
⇒ 9x (x - 20) + 25 (x - 20) = 0
⇒ (9x + 25) (x - 20) = 0
x = and x = 20
But x can't be negative as it represents time.
Therefor, X = 20 minutes.
Time taken by faster pipe to fill the tank = 20 minutes.
Time taken by slowerr pipe to fill the tank = 20+5 = 25 minutes.