Two pipes X and Y can fill a cistern in 24 min. and 32 min. respectively. If both the pipes are opened together, then after how much time Y should be closed so that the tank is full in 18 minutes?

6 min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 min

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 8 min
Let Y closed pipe after a min .
Then part filled by (X+Y) in a min +Part filled by X in (18-x)
So $a (\frac{1}{24} + \frac{1}{32}) + (18 - a) \frac{1}{24} = 1$
Multy by 96
Or 4a+3a+72-4a=96
Or 3x=24
Or x=8 min

Suggest Corrections

Similar questions

Q. Two pipes A and B can fill a cistern in 12 minutes and 16 minutes respectively. If both the pipes are opened together, then after how much time B should be closed so that the tank is full in 9 minutes?

Q. Two pipes A and B can fill a tank in 24 minutes and 32 minutes respectively. If both the pipes are opened simultaneously, after how much time should B be closed so that the tank is full in 18 minutes

Two pipes X and Y can fill a tank in 24 mins and 32 mins each. If both the pipes are started at the same time, after what time should Y be closed to fill up the tank in 18 mins?

Q. Two pipes M & N can fill a cistern in 12 & 16 hrs respectively If both the pipes are opened together then after how many minutes N should be closed so that the tank is full in 9 hours

Q. Two pipes

M

N

can fill a cistern in

12

16

hrs respectively. If both the pipes are opened together, then after how many minutes

N

should be closed so that the tank is full in

9

hrs.

Join BYJU'S Learning Program

Two pipes X and Y can fill a cistern in 24 min. and 32 min. respectively. If both the pipes are opened together, then after how much time Y should be closed so that the tank is full in 18 minutes?

The correct option is B 8 minLet Y closed pipe after a min .Then part filled by (X+Y) in a min +Part filled by X in (18-x) So a(124+132)+(18−a)124=1Multy by 96 Or 4a+3a+72-4a=96Or 3x=24Or x=8 min

The correct option is B 8 min
Let Y closed pipe after a min .
Then part filled by (X+Y) in a min +Part filled by X in (18-x)
So $a (\frac{1}{24} + \frac{1}{32}) + (18 - a) \frac{1}{24} = 1$
Multy by 96
Or 4a+3a+72-4a=96
Or 3x=24
Or x=8 min