Question

# Two place mirrors are inclined at an angle by $$120^o$$, as the figure shows. If a ray strikes mirror $$M_1$$, at a $$65^o$$ angle of incidence, at what angle $$\theta$$ does it leave mirror $$M_2$$.

Solution

## Since from laws of reflection     $$r_{1}=65^{0}$$     then    $$x=90-65 =25^{0}$$Hence from triangle$$x+y+120^{0}=180^{0}$$$$x+y=60^{0}$$$$y=35^{0}$$Hence $$i_{2}=90^{0}-35^{0}=55^{0}$$Hence from laws of reflection$$\theta=i_{2}=55^{0}$$Physics

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