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Question

Two place mirrors are inclined at an angle by $$120^o$$, as the figure shows. If a ray strikes mirror $$M_1$$, at a $$65^o$$ angle of incidence, at what angle $$\theta$$ does it leave mirror $$M_2$$.
512291_556032c7716c41ffbacea06fb003ecbc.png


Solution

Since from laws of reflection     $$r_{1}=65^{0}$$     then    $$x=90-65  =25^{0}$$
Hence from triangle
$$x+y+120^{0}=180^{0}$$
$$x+y=60^{0}$$
$$y=35^{0}$$
Hence $$i_{2}=90^{0}-35^{0}=55^{0}$$
Hence from laws of reflection
$$\theta=i_{2}=55^{0}$$

898833_512291_ans_9252919eb656440f84dd33f42c170659.png

Physics

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