Two plane mirrors A and B are placed parallel to each other at a separation of
40 cm. Alex is standing at a distance of 10 cm from mirror A. What will be the distance between the first set of images of Alex formed by the mirrors?
A
100 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
80 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
60 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 80 cm
Given,
The distance of the object from mirror A = 10 cm
Since object distance from the mirror = image distance from the mirror,
Distance of image (I1) from mirror A = 10 cm
Distance between object and image (I1) = 10 + 10 = 20 cm
The distance of object from mirror B = 40 - 10 = 30 cm
Distance of image (I2) from mirror B = 30 cm
Distance between object and image (I2) = 30 + 30 = 60 cm
Since the images are on either side of the object, the distance between the images will be given by:
Distance of image (I1) from the object + Distance of image (I2) from the object
⇒ 20 + 60 = 80 cm
Thus, the distance between the first set of images of Alex formed by the mirrors is 80 cm.