Question

Two plane mirrors are inclined to one another at an angle of ${60}^{\circ }$. A point object is placed symmetrically between them. If a distance of the object from vertex is $8cm$ then, find the distance between the respective first images formed in both mirrors.

• A. $16cm$
• B. $24cm$
• C. $\frac{8}{\sqrt{3}}cm$
• D. $8\sqrt{3}cm$

Answer 1

The correct option is D $8\sqrt{3}cm$

the angle between both mirrors is ${60}^0$ and distance of vertex from the object is $8cm$ (as given).

The diameter $\left(d\right)$ between both mirror and image will be,
$\frac{sin120}{d}=\frac{sin30}{8}$

$d=2\times 8\frac{\sqrt{3}}{2}=8\sqrt{3}cm$