Two planes are perpendicular to one another one of them contains vectors →a,→c and other contains →b,→d then (→a×→c).(→b×→d)=
A
1
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B
0
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C
−1
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D
none of these
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Solution
The correct option is C0 →n1 & →n2 are 2 normal vector from plane 1 & plane 2 respectively →n1=→a×→c →n2=→b×→d As two planes are ⊥ to each other than n1 & n2 are ⊥ to each other →n1⋅→n2=0 (→a×→c).(→b×→d)=0