Two planets have radii r1 and r2 and their densities are -1 and -2- respectively- The ratio of acceleration due to gravity on them will be-

The correct option is A r_1ρ_1:r_2ρ_2 g _ 1 g _ 2 = GM _ 1 r _ 1 ^ 2 ÷ GM _ 2 r _ 2 ^ 2 = Gp _ 1 4 3 π r _ 1 ^ 3 r _ 1 ^ 2 ÷ Gp _ 2 4 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Gravitational Force

Two planets h...

Question

Two planets have radii $r_{1}$ and $r_{2}$ and their densities are $ρ_{1}$ and $ρ_{2}$ , respectively. The ratio of acceleration due to gravity on them will be.

r_{1} ρ_{1} : r_{2} ρ_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

r_{1} ρ_{1}^{2} : r_{2} ρ_{2}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

r_{1}^{2} ρ_{1} : r_{2}^{2} ρ_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

r_{1} ρ_{2} : r_{2} ρ_{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $r_{1} ρ_{1} : r_{2} ρ_{2}$
$\frac{g_{1}}{g_{2}} = \frac{{G M}_{1}}{r_{1}^{2}} \div \frac{{G M}_{2}}{r_{2}^{2}}$
$= \frac{{G p}_{1} \frac{4}{3} π r_{1}^{3}}{r_{1}^{2}} \div \frac{{G p}_{2} \frac{4}{3} π r_{2}^{3}}{r_{2}^{2}}$
$= \frac{p_{1} r_{1}}{p_{2} r_{2}}$
$= \frac{r_{1} p_{1}}{r_{2} p_{2}}$
$= r_{1} p_{1} : r_{2} p_{2}$

Suggest Corrections

Similar questions

The radii of two planets are respectively $R_{1}$ and $R_{2}$ and their densities are respectively $ρ_{1} a n d ρ_{2}$ . The ratio of the accelerations due to gravity at their surface is

Q. The radii of two planets are

R_{1}

and

R_{2}

, respectively, and their densities are,

ρ_{1}

and

ρ_{2}

respectively. What is the ratio of the acceleration due to gravity at their surfaces?

Q. The radii of two planets are respectively

R_{1}

and

R_{2}

and their densities are respectively

ρ_{1}

and

ρ_{2}

. The ratio of the accelerations due to gravity

(g_{1} / g_{2})

at their surfaces is:

Q. The radii of two planets are

R_{1}

and

R_{2}

respectively and their densities are

ρ_{1}

and

ρ_{2}

respectively. The ratio of the accelerations due to gravity

\frac{g_{1}}{g_{2}}

at their surfaces is

Q. The radii of two planets are respectively

R_{1}

and

R_{2}

, and their densities are respectively

ρ_{1}

and

ρ_{2}

. The ratio of the acceleration due to gravity at their surface is

Join BYJU'S Learning Program

Two planets have radii r1 and r2 and their densities are ρ1 and ρ2, respectively. The ratio of acceleration due to gravity on them will be.

The correct option is A r1ρ1:r2ρ2g1g2=GM1r21÷GM2r22=Gp143πr31r21÷Gp243πr32r22=p1r1p2r2=r1p1r2p2=r1p1:r2p2

Two planets have radii $r_{1}$ and $r_{2}$ and their densities are $ρ_{1}$ and $ρ_{2}$ , respectively. The ratio of acceleration due to gravity on them will be.