You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Acceleration Due to Gravity

Two planets h...

Question

Two planets have the same average density but their radii are $R_{1}$ and $R_{2}$ . If acceleration due to gravity on these planets be $g_{1}$ and $g_{2}$ respectively, then

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

$g = \frac{4}{3} π ρ G R .$ If $ρ$ = constant then $\frac{g_{1}}{g_{2}} = \frac{R_{1}}{R_{2}}$

Suggest Corrections

Similar questions

The radii of two planets are respectively $R_{1}$ and $R_{2}$ and their densities are respectively $ρ_{1} a n d ρ_{2}$ . The ratio of the accelerations due to gravity at their surface is

Two planets of radii $r_{1}$ and $r_{2}$ are made from the same material. The ratio of the acceleration due to gravity $\frac{g_{1}}{g_{2}}$ at the surface of the two planets is

Q. The radii of two planets are respectively

R_{1}

and

R_{2}

and their densities are respectively

ρ_{1}

and

ρ_{2}

. The ratio of the accelerations due to gravity

(g_{1} / g_{2})

at their surfaces is:

Q. The radii of two planets are

R_{1}

and

R_{2}

respectively and their densities are

ρ_{1}

and

ρ_{2}

respectively. The ratio of the accelerations due to gravity

\frac{g_{1}}{g_{2}}

at their surfaces is

Two planets of radii $r_{1}$ and $r_{2}$ are made from the same material. The ratio of the acceleration due to gravity $\frac{g_{1}}{g_{2}}$ at the surface of the two planets is:

Join BYJU'S Learning Program

Two planets have the same average density but their radii are R1 and R2. If acceleration due to gravity on these planets be g1 and g2 respectively, then

The correct option is A g=43πρ GR. If ρ = constant then g1g2=R1R2

Two planets have the same average density but their radii are $R_{1}$ and $R_{2}$ . If acceleration due to gravity on these planets be $g_{1}$ and $g_{2}$ respectively, then

The correct option is A

$g = \frac{4}{3} π ρ G R .$ If $ρ$ = constant then $\frac{g_{1}}{g_{2}} = \frac{R_{1}}{R_{2}}$