Two planets move around the sun. The time periods and the mean radii of the orbits are $T_{1}, T_{2} a n d r_{1}, r_{2}$ respectively. The ratio $\frac{T_{1}}{T_{2}}$ is equal to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D

$T^{2} \propto r^{3} \Rightarrow \frac{T_{1}}{T_{2}} = (\frac{r_{1}}{r_{2}})^{\frac{3}{2}}$

Suggest Corrections

Similar questions

Two planets move around the sun. The periodic times and the mean radii of the orbits are $T_{1}, T_{2} a n d r_{1}, r_{2}$ respectively. The ratio $\frac{T_{1}}{T_{2}}$ is equal to

Q. The time periods and the mean radii of the orbits of two planets around Sun are

T_{1}, T_{2} a n d r_{1}, r_{2}

respectively. The ratio

\frac{T_{1}}{T_{2}}

is equal to .

Two planets move around the sun. The periodic times and the mean radii of the orbits are $T_{1}, T_{2} a n d r_{1}, r_{2}$ respectively. The ratio $\frac{T_{1}}{T_{2}}$ is equal to

Q. Two plates move around the Sun. The periodic times and the mean radii of the orbits are

T_{1}, T_{2}

and

r_{1}, r_{2}

respectively. The ratio

\frac{T_{1}}{T_{2}}

is equal to.

The half life of a ratio active source is T. If radio activities of the samples are $R_{1} - R_{2}$ at time

$T_{1} a n d T_{2}$ Respectively, then the number of atoms disintegrated in time $(T_{2} - T_{1})$ is proportional to

Join BYJU'S Learning Program

Two planets move around the sun. The time periods and the mean radii of the orbits are T1,T2 and r1,r2 respectively. The ratio T1T2 is equal to

The correct option is D T2∝r3⇒T1T2=(r1r2)32

Two planets move around the sun. The time periods and the mean radii of the orbits are $T_{1}, T_{2} a n d r_{1}, r_{2}$ respectively. The ratio $\frac{T_{1}}{T_{2}}$ is equal to

The correct option is D

$T^{2} \propto r^{3} \Rightarrow \frac{T_{1}}{T_{2}} = (\frac{r_{1}}{r_{2}})^{\frac{3}{2}}$