Two planets revolves around the sun with frequencies N1 and N2 revolutions per year. If their average radii (orbital) be R1 and R2 respectively, then R1/R2 is equal to:
A
(N1/N2)2/3
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B
(N1/N2)3/2
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C
(N2/N1)2/3
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D
(N2/N1)3/2
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Solution
The correct option is B(N2/N1)2/3 According to Kepler's law of planetary motion T2∝R3 If N is frequency then N2∝(R)−3 or N2N1(R2R1)−3/2 ⇒R1R2=(N2N1)2/3