Two plates are at potential -10V and 30V. If the separation between them is 2cm. The electric field between them is
1) 2000 V/m
2) 1000 V/m
3) 500 V/m

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Solution

The electric field is given by the equation

E=v/d

V= the potential difference= 30-(-10)=40
d= seperation= 2×10^-2 m

therefore E=v/d= 40/(2*10^-2) = 2000V/m

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Two plates are at potential -10V and 30V. If the separation between them is 2cm. The electric field between them is 1) 2000 V/m 2) 1000 V/m 3) 500 V/m

The electric field is given by the equation E=v/d V= the potential difference= 30-(-10)=40 d= seperation= 2×10^-2 m therefore E=v/d= 40/(2*10^-2) = 2000V/m

Two plates are at potential -10V and 30V. If the separation between them is 2cm. The electric field between them is
1) 2000 V/m
2) 1000 V/m
3) 500 V/m

The electric field is given by the equation

E=v/d

V= the potential difference= 30-(-10)=40
d= seperation= 2×10^-2 m

therefore E=v/d= 40/(2*10^-2) = 2000V/m