Question

Two plates are connected by fillet welds of size 8 mm and subjected to a tensile force of 350 kN. The thickness of each plate is 12 mm. The yield stress and ultimate stress of steel are 250 MPa and 410 MPa respectively. As per IS 800 : 2007, the length (l) required to transmit the load is ____mm. (The welding is done at site).

• A. 119.14
• B. 196
• C. 148
• D. 296

Answer 1

The correct option is C 148

Given, size of weld,
$S=8mm$;

Effective throat thickness
$\left(t_t\right)=(0.7\times S)=(0.7\times 8)=5.6mm$

$f_u=410MPa,f_y=250MPa,{\gamma }_{mw}=1.5\text{(at site)}$

Strength of weld per mm length
$=\left(\frac{f_u}{\sqrt{3}}\right)\frac{t_t}{{\gamma }_{mw}}$
$=\left(\frac{410}{\sqrt{3}}\right)\frac{5.6}{1.5}$
$=883.73N/mm$

$\therefore \text{Length of weld required to transmit 350 kN load}$
$2L+100=\frac{350\times {10}^3}{883.73}$
$2L+100=396$
$L=148mm$