1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Charging by Induction
two plates (a...
Question
two plates (area =s) charged to +q1 and +q2 (q2>q1) are brought close to form capacitor of capacitance C. the potential difference across the plates is -
Open in App
Solution
Suggest Corrections
21
Similar questions
Q.
Two plates (area =
5
) charged to
+
q
1
and
+
q
2
(
q
2
<
q
1
)
are brought closer to form a capacitor of capacitance
C
. The potential difference across the plates is :
Q.
Two identical metal plates are given positive charge
Q
1
and
Q
2
(
<
Q
1
)
respectively. If they are now brought close together to form a parallel plate capacitor with capacitance
C
, the potential difference between them is
Q.
Two parallel plates have charges
Q
1
and
Q
2
on them and the capacitance is c. The potential difference between them is
Q.
An isolated parallel plate capacitor of capacitance
C
has four surfaces with charges
Q
1
,
Q
2
,
Q
3
and
Q
4
as shown in the figure below. The potential difference across plates is (In the given diagram,
Q
1
and
Q
4
are the charges on the outer surfaces of the left & right plates respectively)
Q.
Charges
Q
1
and
Q
2
are given to two plates of a parallel plate capacitor. The capacity of the capacitor is
C
. When the switch is closed, mark the correct statement(s): (Assume both
Q
1
and
Q
2
to be positive)
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Conductors, Insulators and Methods of Charging
PHYSICS
Watch in App
Explore more
Charging by Induction
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app