Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode. The colourless solutions contains:

platinum sulphate

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copper hydroxide

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copper sulphate

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sulphuric acid

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Solution

The correct option is D sulphuric acid
When $C u S O_{4}$ dissolves in solution, $C u^{+ 2}$ reduces at cathode as its reduction potential is higher than hydrogen ion.
and $O H^{-}$ ion oxidises at anode and oxygen gas evolves.
So remaining ions ( $H^{+}, S O_{4}^{- 2}$ ) in solution forms $H_{2} S O_{4}$ acid.

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Q. Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode.

The colourless solutions contains:

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Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode. The colourless solutions contains:

The correct option is D sulphuric acidWhen CuSO4 dissolves in solution, Cu+2 reduces at cathode as its reduction potential is higher than hydrogen ion.and OH− ion oxidises at anode and oxygen gas evolves.So remaining ions (H+,SO−24) in solution forms H2SO4 acid.