Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode.
The colourless solutions contains:

Copper Sulphate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Sulphuric Acid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Copper hydroxide

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Sulphuric Acid
$2 H^{+}$ + $S O_{4}^{2 -}$ $\to$ $H_{2} S O_{4}$

Since it is said that solution is colourless.

$∴$ it should be ${H_{2} S O}_{4}$ . Since copper sulphate and copper hydroxide are coloured

Suggest Corrections

Similar questions

Two platinum electrodes were immersed in a solution of CuSO $_{4}$ and current was passed through the solution. After sometime it was found that colour of CuSO $_{4}$ disappeared with the evolution of gas at the electrode. The colourless solution contains:

Q. Direct current is passed through copper sulphate solution using platinum electrodes. The elements liberated at the electrodes are :

When an electric current is passed through a solution containing copper sulphate, copper gets deposited on which electrode?

Q. An electric current is passed through silver nitrate solution using silver electrodes.

15.28

g of silver was found to be deposited on cathode. What will be the weight of copper deposited on cathode if same amount of electricity is passed through copper sulphate solution using copper electrodes?

Assertion: Upal observed that copper is deposited on the negative electrode connected to the terminal of the battery. Kavya performed the same experiment but she replaced the copper electrode with a carbon electrode and still observed copper is deposited over carbon rod.

Reason: Copper sulphate solution dissociates into copper and sulphate ions when electricity is passed through dilute copper sulphate solution and this free copper ions deposit on the carbon rod.

Join BYJU'S Learning Program

Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode. The colourless solutions contains:

The correct option is B Sulphuric Acid2H+ + SO2−4 → H2SO4Since it is said that solution is colourless.∴ it should be H2SO4. Since copper sulphate and copper hydroxide are coloured

Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode.
The colourless solutions contains:

The correct option is B Sulphuric Acid
$2 H^{+}$ + $S O_{4}^{2 -}$ $\to$ $H_{2} S O_{4}$

Since it is said that solution is colourless.

$∴$ it should be ${H_{2} S O}_{4}$ . Since copper sulphate and copper hydroxide are coloured