Question

Two-point charges 3$\mu c$ and 6 $\mu c$ are separated through a distance of 1 m in the air. Find the result electric intensity at the midway between them.

Answer 1

Given,

$q_1=3\mu C$

$q_2=6\mu C$

In figure,

The electric field intensity at mid point due to charge $q_1$

$E_1=\frac{1}{4\pi {\epsilon }_0}.\frac{q_1}{(0.5{)}^2}$

$E_1=9\times {10}^9\times \frac{3\times {10}^{-6}}{(0.5{)}^2}$

$E_1=36kN/C$

The electric field intensity at mid point due to charge $q_2$

$E_2=\frac{1}{4\pi {\epsilon }_0}\frac{q_2}{(0.5{)}^2}$

$E_2=9\times {10}^9\times \frac{6\times {110}^{-6}}{(0.5{)}^2}$

$E_2=216kN/C$

Both electric field intensity are in opposite direction,

The net electric field intensity at mid point is given by

$E_n=E_2-E_1$

$E_n=(216-36)kN/C$

$E_n=1.8\times {10}^{5}N/C$