Two point charges +4C and +6C repel each other with a force F. If a charge −5C is given to each of these charges, the force becomes:
A
repulsive force of F24
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B
attractive force of F24
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C
repulsive force 24F
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D
attractive force 24F
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Solution
The correct option is B attractive force of F24 ⇒GivenF=K(4)(6)r2 Initially as both charges have similar sign there exist repulsion force when −5C is given the charges become opposite and attract each other. Fnew=K(−1)(1)r2
FnewF=−Kr2K×24r2
Fnew=−F24
(negative sign here implies the attractive nature of force)