Two point charges +8μC and +12μC repel each other with a force of 48 N. When an additional charge of −10μC is given to each of these charges (the distance between the charges is unaltered), then the new force is:
q1=+8 μC
q2=+12 μC
F1=48 N
Now, q′1=−2 μC
and, q′2=+2 μC
So, F1F2=q1q2q′1q′2
F2=2N