Question

# Two point charges $$+8q$$ and $$-2q$$ are located at $$x=0$$ and $$x=L$$ respectively. The location of a point on the x axis at which the net electric field due to these two point charges is zero is :

A
L4
B
2L
C
4L
D
8L

Solution

## The correct option is B $$2L$$ The net electric field at P is $$E=k\dfrac{8q}{x^2}+k\dfrac{(-2q)}{(x-L)^2}=0$$ $$\Rightarrow \dfrac{4}{x^2}=\dfrac{1}{(x-L)^2}$$ $$\Rightarrow \dfrac{2}{x}=\dfrac{1}{(x-L)}$$ or $$x=2x-2L \Rightarrow x=2L$$ PhysicsNCERTStandard XII

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More