wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two point charges a and b whose magnitudes are same are positioned at a certain distance from each other along the positive x− axis. a is placed at the origin. A graph is plotted between the electric field strength and distance x (measured from a). E is taken to be positive if it is along the line joining the two charges from a to b. From the graph it can be decided that


A
a is positive, b is negative
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a is negative, b is positive
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a and b both are negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a and b both are positive
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A a is positive, b is negative
From the graph it is evident that the field is always in the positive direction and it is not zero at any point.

If both a and b are positive or negative then there must exist a point between them where the field must be zero. Since, that is not reflected in the graph these two options can be neglected.

If a is negative and b is positive, then the direction of the electric field will be from b to a. According to the convention we have chosen, the field will always be negative. Since, in our graph the field is always positive. Hence, this option can be neglected too.

This means that a must be positive and b must be negative.

Hence, option (a) is the correct answer.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon