Two point charges are located on the x-axis: q1=−e at x=0 and q2=+e at x=a. A third point charge q3=+e is brought to x=2a.The total potential energy of the system of three charges is :
A
e24πε0a
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B
e28πε0a
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C
−e28πε0a
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D
−e24πε0a
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Solution
The correct option is C−e28πε0a Third charge q3 is brought to x=2a.
Potential energy of q1,q2 system=14πϵ0−e2a
Potential energy of q2,q3 system=14πϵ0+e2a
Potential energy of q2,q3 system=14πϵ0−e22a
Hence total energy of the system of three particles=−e28πϵ0a