Two point charges of 50 microC and 20 microC are separated by a distance of 2 m. Find the point on the line joining them at which electric field intensity is zero

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Solution

This point can be found out by taking the algebraic sum of the potential due to both the charges equal to zero.

For example if we place two positive charges Q and q are placed at a distance r apart then find the point at which potential is zero.

We find it by considering a point at a distance x from charge Q on the joining line. Thus,

here

r = 2m

Q = 50 μC

q = 20 μC

so,

VQ + Vq = 0

or

kQ / x + kq / (r-x) = 0

or

5μC / x +20μC / (2-x) = 0

or

1/x =- 4/(2-x) {dividing by5}

or

2-x = -4x

x=-3/2

thus, the point at which potential would be zero will be at

x = -3/2 = -1.5 m

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