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Question

# Two point charges of 50 microC and 20 microC are separated by a distance of 2 m. Find the point on the line joining them at which electric field intensity is zero

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Solution

## This point can be found out by taking the algebraic sum of the potential due to both the charges equal to zero. For example if we place two positive charges Q and q are placed at a distance r apart then find the point at which potential is zero. We find it by considering a point at a distance x from charge Q on the joining line. Thus, here r = 2m Q = 50 μC q = 20 μC so, VQ + Vq = 0 or kQ / x + kq / (r-x) = 0 or 5μC / x +20μC / (2-x) = 0 or 1/x =- 4/(2-x) {dividing by5} or 2-x = -4x x=-3/2 thus, the point at which potential would be zero will be at x = -3/2 = -1.5 m

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